As discussed previously, we understand how important a role the topic, ‘equations’ plays in solving most of the questions in the Quantitative Aptitude section of any major competitive exam, such as IBPS PO, IBPS Clerk, SBI PO, SBI Clerk, SSC CGL, SSC CHSL and other competitive exams and more. We have also learnt the different types of equations, what linear equation is and how to solve them.

Here, let us talk about what is quadratic equation and how to solve them easily.

**What is Quadratic Equation?**

In a Quadratic Equation, all the powers of the variable are positive and the highest power is 2. Hence, we can also say that it is a second-degree polynomial which is equated to zero.

**roots of the equation.**

**How To Find The Roots Of A Quadratic Equation?**

**First Method: Standard Method**

**Second Method: Factorization**

In factorization method, a quadratic equation is written in terms of two simple linear equations. Sometimes, it may not be simple to solve a quadratic equation in this method. In which case, we can always solve the equation in the standard method.

Example 1:

Quadratic equation with 2 variable:

Solution:

**First Method: Standard Formula**

**Second Method: Factorization**

Example 2:

Solve the given equation and establish the relationship between x and y.

Solution:

We have to solve these equations separately and find out the values of x and y.

First Equation:

Second Equation:

Solve the given equation and establish the relationship between x and y.

Solution:

We have to solve these equations separately and find out the values of x and y.

First Equation:

Second Equation:

**How to easily split the constant ‘b’:**1. We can use the trail and error method.

2. Find b1 such that

**b1**

**is a multiple of a**AND b2 such that

**b2**

**is a factor of c**.

**48 = 51 – 3 and 51 * 3 = 153**

**32 = 26 + 6 and 26 * 6 = 156**

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